[英]c++ template and iterator
I am trying to declare this function : 我想宣布这个功能:
template <typename T> void hi(std::map<T,double> m,std::vector<std::map<T,double>::iterator > vec)
{
//....
}
I want the function to have as parameters a map of and a vector of iterators on this map. 我希望函数在此映射上具有迭代器的映射和向量作为参数。 But the g++ compiler does not seem to like it and I receive the following error :
但g ++编译器似乎不喜欢它,我收到以下错误:
type/value mismatch at argument 1 in template parameter list for ‘template<class _Tp, class _Alloc> class std::vector’
: error: expected a type, got ‘std::map::iterator’
: error: template argument 2 is invalid
Any help please? 有什么帮助吗?
You must write typename
before the iterator argument 您必须在迭代器参数之前写入
typename
template <typename T>
void hi(std::map<T,double> m, std::vector<typename std::map<T,double>::iterator > vec)
^^^^^^^^
{
//....
}
Yes, it is unfortunate that typename
has 2 different meanings. 是的,不幸的是,
typename
有两种不同的含义。 Some authors use template<class T>
for precisely that reason, in order to visually disambiguate template parameter declarations from dependent type extraction. 一些作者正是出于这个原因使用
template<class T>
,以便在视觉上消除模板参数声明与依赖类型提取的歧义。 Especially in template-metaprogramming this can help to make code a bit more readable. 特别是在模板元编程中,这有助于使代码更具可读性。
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