Javascript运行对象和所有这些方法

Question

I've created the following jQuery OOP code

(function ($) {

    example = {
      method1 : function()  {},
      method2   : function()  {}        
    };


})(jQuery);

I don't want to use init() and call some methods on document ready. Is there any way to execute/run the object in literal notation?? I used var example = new Object(); but I'm getting error, I just need all the methods associated to the objects to be running on ready.

Answer 1

This will do it :)

(function ($) {

    // define some methods
    var example = {
      method1: function() { console.log(1); },
      method2: function() { console.log(2); }        
    };

    // run all methods in example
    for (var m in example) {
      if (example.hasOwnProperty(m) && typeof example[m] === "function") {
        example[m]();
      }
    }

    // => 1
    // => 2

})(jQuery);

---

If you want to use new such as

var example = new Example();
// => "A"
// => "B"

You could do something like this

(function($) {

  var Example = function() {
    this.initializeA();
    this.initializeB();  
  };

  Example.prototype.initializeA = function() {
    console.log('A');
  }

  Example.prototype.initializeB = function() {
    console.log('B');
  };

  // init
  new Example();
  // => "A"
  // => "B"

})(jQuery);

Answer 2

Perhaps this is what you're looking for?

(function ($) {

    example = (function() {alert("some code")})();
    //or
    (function() {alert("some other code")})();
    //or
    alert("even more code");

})(jQuery);