Java排序价格值的升序和降序

Question

I have the price Values in String format ("2,000","3,000" etc)

I want to Sort the Price Values

for that I have used the Below Code:

Comparator<Cars> comparator = new Comparator<Cars>() {

          @Override
          public int compare(Cars object1, Cars object2) {
          // return Float.compare(Integer.parseInt(object1.getPrice()), Integer.parseInt(object2.getPrice()));

           return ((Integer)Integer.parseInt(object1.getPrice())).compareTo((Integer)Integer.parseInt( object2.getPrice())); 

          }

If i execute the Below Statement

        Collections.sort(carsList, comparator);

I'm getting

Error:  java.lang.NumberFormatException: Invalid int: "3,000"

Could any one help?

Answer 1

Integer.parseInt() will not work with currency containing commas( , ). You may have to do the string manipulation to remove the comma before trying to use the parseInt() method.

Doing something like this:

String obj1Price = object1.getPrice().replaceAll(",","");
String obj2Price = object2.getPrice().replaceAll(",","");

return ((Integer)Integer.parseInt(obj1Price )).compareTo((Integer)Integer.parseInt( obj2Price))); 

Answer 2

在将货币数据（字符串表示形式）传递给您的方法之前，对其进行修改，例如，您可以使用以下方法：

"2,000".replaceAll(",","");

Answer 3

Integer.parseInt("3,000")

is throwing the exception. You need to get rid off , from the string representation of your price.

Look here .

Answer 4

Try this

Comparator<String> comparator = new Comparator<String>() {

              @Override
              public int compare(String object1, String object2) {
                  int i = 0;
                int j = 0;
                try {
                    i = NumberFormat.getNumberInstance(java.util.Locale.US).parse(object1).intValue();
                      j = NumberFormat.getNumberInstance(java.util.Locale.US).parse(object2).intValue();
                } catch (ParseException e) {
                }
              // return Float.compare(Integer.parseInt(object1.getPrice()), Integer.parseInt(object2.getPrice()));
                    System.out.println("i = " + ((Integer)i) + " , j = " + ((Integer)j));

               return ((Integer)i).compareTo(((Integer)j)); 

              } 
          };
            System.out.println("xxxxxxxxx = " + comparator.compare("4,000", "3,000"));

Answer 5

return ((Integer)Integer.parseInt(obj1Price.replaceAll(",","") )).compareTo((Integer)Integer.parseInt( obj2Price.replaceAll(",",""))));

将工作