如何用BASH中另一个文件中的行替换CSV文件的列？

Question

I have a 4-column CSV file, data.csv using "@" as the separator, eg:

1@fish@ocean@likes to swim in the ocean
2@whale@ocean@likes to swim in the ocean

To edit just the 4th column, I used this command:

awk -F "@*" '{print $4}' data.csv > temp.csv

Then I ran some additional scripts to modify temp.csv .

Now, I need to return the contents of temp.csv to data.csv , replacing everything in the 4th column of data.csv .

How can I replace the contents of the 4th column of data.csv with the edited lines in temp.csv ?

Answer 1

你也可以使用paste和cut ：

cut -d@ -f1-3 data.csv | paste -d@ - temp.csv

Answer 2

I upvoted the other answer, but to give you an idea of the approach in awk:

Having first prepared your temp.csv file:

$ cut -d@ -f4 data.csv | sed -e 's,ocean,lava,g' > temp.csv

You then read a line from temp.csv as you read each line from data.csv , overwriting the fourth field in the line:

$ awk -F@ -vOFS=@ '{ getline $4 < "temp.csv" ; print }' data.csv
1@fish@ocean@likes to swim in the lava
2@whale@ocean@likes to swim in the lava