[英]Numpy array of random matrices
I'm new to python/numpy and I need to create an array containing matrices of random numbers. 我是python / numpy的新手,我需要创建一个包含随机数矩阵的数组。
What I've got so far is this: 到目前为止我得到的是:
for i in xrange(samples):
SPN[] = np.random.random((6,5)) * np.random.randint(0,100)
Which make sense for me as PHP developer but is not working for python. 这对我作为PHP开发人员有意义,但不适用于python。 So how do I create a 3 dimensional array to contain this matrices/arrays? 那么如何创建一个包含这个矩阵/数组的三维数组呢?
Both np.random.randint
and np.random.uniform
, like most of the np.random
functions, accept a size
parameter, so in numpy
we'd do it in one step: 像大多数np.random
函数一样, np.random.randint
和np.random.uniform
都接受一个size
参数,所以在numpy
我们只需要一步完成:
>>> SPN = np.random.randint(0, 100, (3, 6, 5))
>>> SPN
array([[[45, 95, 56, 78, 90],
[87, 68, 24, 62, 12],
[11, 26, 75, 57, 12],
[95, 87, 47, 69, 90],
[58, 24, 49, 62, 85],
[38, 5, 57, 63, 16]],
[[61, 67, 73, 23, 34],
[41, 3, 69, 79, 48],
[22, 40, 22, 18, 41],
[86, 23, 58, 38, 69],
[98, 60, 70, 71, 3],
[44, 8, 33, 86, 66]],
[[62, 45, 56, 80, 22],
[27, 95, 55, 87, 22],
[42, 17, 48, 96, 65],
[36, 64, 1, 85, 31],
[10, 13, 15, 7, 92],
[27, 74, 31, 91, 60]]])
>>> SPN.shape
(3, 6, 5)
>>> SPN[0].shape
(6, 5)
.. actually, it looks like you may want np.random.uniform(0, 100, (samples, 6, 5))
, because you want the elements to be floating point, not integers. ..实际上,看起来你可能想要np.random.uniform(0, 100, (samples, 6, 5))
,因为你希望元素是浮点数,而不是整数。 Well, it works the same way. 嗯,它的工作方式相同。 :^) :^)
Note that what you did isn't equivalent to np.random.uniform
, because you're choosing an array of values between 0 and 1 and then multiplying all of them by a fixed integer. 请注意,您所做的并不等同于np.random.uniform
,因为您选择的值介于0和1之间,然后将所有值乘以固定的整数。 I'm assuming that wasn't actually what you were trying to do, because it's a little unusual; 我假设那不是你想要做的事情,因为它有点不寻常; please comment if that is what you actually wanted. 请评论,如果这是你真正想要的。
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