[英]Regex getting two specific characters within square brackets
Not too well-versed with Regex. 对Regex不太了解。 I have a string like this: 我有一个像这样的字符串:
var str = "WOMEN~~Accessories >Underwear~~Socks, Tights & Leggings"
Using Javascript, I want to split at: ~~
, &
, >
and ,
including potential white space surrounding them. 我想使用Javascript分割: ~~
, &
, >
和,
包括它们周围的潜在空白。
So far I've got: 到目前为止,我已经:
var arr = str.split(/[\s>&,]/g);
for (var i = 0; i<arr.length; i++){
if(arr[i]){accepted.push(arr[i])}
}
This doesn't account for multiple characters though (and I'm sure there's a better way to regex in the white space rather than a for
loop after the fact!) and the ~~
isn't selected. 但是,这并不能解决多个字符(我相信有一种更好的方式在空白中进行正则表达式,而不是事实之后的for
循环!),并且未选择~~
。
I'm thinking something along the lines of /[\\s>&,[~~]]/g
but this doesn't work. 我在想类似/[\\s>&,[~~]]/g
但这是行不通的。 How can I do this with regex? 我该如何使用正则表达式呢?
Try this: 尝试这个:
/\s*[\s>&,\[\]~]+\s*/g
var arr = str.split(/(~~|[\s>&,]+)/g);
因此,您将拆分~~或空格,&符,大于(>)和逗号的任意组合。
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