Regex getting two specific characters within square brackets

Question

Not too well-versed with Regex. I have a string like this:

 var str = "WOMEN~~Accessories >Underwear~~Socks, Tights & Leggings"

Using Javascript, I want to split at: ~~ , & , > and , including potential white space surrounding them.

So far I've got:

 var arr = str.split(/[\s>&,]/g);
 for (var i = 0; i<arr.length; i++){
    if(arr[i]){accepted.push(arr[i])}
 }

This doesn't account for multiple characters though (and I'm sure there's a better way to regex in the white space rather than a for loop after the fact!) and the ~~ isn't selected.

I'm thinking something along the lines of /[\\s>&,[~~]]/g but this doesn't work. How can I do this with regex?

Answer 1

Try this:

/\s*[\s>&,\[\]~]+\s*/g

Description

Demo

http://jsfiddle.net/p7FFD/

Answer 2

var arr = str.split(/(~~|[\s>&,]+)/g);

因此，您将拆分~~或空格，＆符，大于（>）和逗号的任意组合。