json_encode用php作为javascript函数的参数

Question

i need a help to json_encode

i have a html

<a class="list_size" onclick="generate_size(<?php echo htmlspecialchars(json_encode($ukuran));?>);return false;" title="<?php echo $warna[$w]['warna']; ?>"><?php echo $warna[$w]['warna']; ?></a>

and this is the json of php variable of $ukuran

echo json_encode($ukuran);
output : [{"uk":"26"},{"uk":"27"},{"uk":"28"},{"uk":"29"},{"uk":"30"},{"uk":"31"},{"uk":"32"},{"uk":"33"},{"uk":"34"},{"uk":"35"}]

and this is the function of javascript

function generate_size(ukuran) {

    alert(ukuran.length + ukuran.uk[0])
}

when i using alert(ukuran.length) that will shown alert with 10, and that is correct.. but when i using alert(ukuran.length + ukuran.uk[0]) i fail tu call this function..

if i see the json_encode above, if i alert(ukuran.uk[0]) that should be shown 26

how to solve this problem.. i try to found it at google but not found working solution, can someone help me?? thanks

Answer 1

似乎ukuran [0]是{“uk”：“26”}而不仅仅是26.你确定你不是在寻找ukuran [0] .uk？

Answer 2

尝试将字符串转换为int

alert(ukuran.length + parseInt(ukuran.uk[0]));