[英]MergeSort Implementation in C#
Currently studying algorithm analysis, and instead of blindly running off of pseudo-code from my textbook, I'm implementing each algorithm in C#.目前正在研究算法分析,而不是盲目地从我的教科书中跑掉伪代码,我正在用 C# 实现每个算法。 This is the psuedo-code:
这是伪代码:
MERGE-SORT(A,p,r)
1 if p < r
2 q = (p+r)/2
3 MERGE-SORT(A,p,q)
4 MERGE-SORT(A,q+1,r)
5 MERGE(A,p,q,r)
MERGE(A,p,q,r)
1 n1 = q - p + 1
2 n2 = r - q
3 let L[1..n1+1] and R[1..n2+1] be new arrays
4 for i = 1 to n1
5 L[i] = A[p+i-1]
6 for j = 1 to n2
7 R[j] = A[q+j]
8 L[n1+1] = INF
9 R[n1+1] = INF
10 i = 1
11 j = 1
12 for k = p to r
13 if L[i] <= R[j]
14 A[k] = L[i]
15 i = i + 1
16 else
17 A[k] = R[j]
18 j = j + 1
This is my code:这是我的代码:
static void Main(string[] args)
{
int[] unsortedArray = new int[] { 5, 2, 7, 4, 1, 6, 8, 3, 9, 10 };
MergeSort(ref unsortedArray, 1, unsortedArray.Length);
foreach (int element in unsortedArray)
{
Console.WriteLine(element);
}
Console.Read();
}
private static void MergeSort(ref int[] unsortedArray, int leftIndex, int rightIndex)
{
if (leftIndex < rightIndex)
{
int middleIndex = (leftIndex + rightIndex) / 2;
//Sort left (will call Merge to produce a fully sorted left array)
MergeSort(ref unsortedArray, leftIndex, middleIndex);
//Sort right (will call Merge to produce a fully sorted right array)
MergeSort(ref unsortedArray, middleIndex + 1, rightIndex);
//Merge the sorted left & right to finish off.
Merge(ref unsortedArray, leftIndex, middleIndex, rightIndex);
}
}
private static void Merge(ref int[] unsortedArray, int leftIndex, int middleIndex, int rightIndex)
{
int lengthLeft = middleIndex - leftIndex + 1;
int lengthRight = rightIndex - middleIndex;
int[] leftArray = new int[lengthLeft + 1];
int[] rightArray = new int[lengthRight + 1];
for (int i = 0; i < lengthLeft; i++)
{
leftArray[i] = unsortedArray[leftIndex + i - 1];
}
for (int j = 0; j < lengthRight; j++)
{
rightArray[j] = unsortedArray[middleIndex + j];
}
leftArray[lengthLeft] = Int32.MaxValue;
rightArray[lengthRight] = Int32.MaxValue;
int iIndex = 0;
int jIndex = 0;
for (int k = leftIndex; k < rightIndex; k++)
{
if (leftArray[iIndex] <= rightArray[jIndex])
{
unsortedArray[k] = leftArray[iIndex];
iIndex++;
}
else
{
unsortedArray[k] = rightArray[jIndex];
jIndex++;
}
}
}
I'm not sure where I'm messing things up -- I tried to follow the pseudo-code as well as I could, but my output is funky (ie repeated values and not properly sorted).我不确定我在哪里搞砸了 - 我试图尽可能地遵循伪代码,但我的输出很时髦(即重复的值并且没有正确排序)。
Debugging this didn't help me figure out the problem either (recursive solutions get too messy).调试这个也没有帮助我找出问题(递归解决方案变得太混乱了)。
Where am I going wrong, and how do I fix it?我哪里出错了,我该如何解决?
As correctly pointed out in the comments, C# array indexing is zero-based, while your pseudo code is one-based.正如评论中正确指出的那样,C# 数组索引是从零开始的,而您的伪代码是从一开始的。
That being said, here's the errors:话虽如此,这里是错误:
1) Main method 1) 主要方法
MergeSort(ref unsortedArray, 1, unsortedArray.Length);
has to be changed to:必须改为:
MergeSort(ref unsortedArray, 0, unsortedArray.Length - 1);
2) Merge method 2)合并方法
leftArray[i] = unsortedArray[leftIndex + i - 1];
has to be change to:必须改为:
leftArray[i] = unsortedArray[leftIndex + i];
3) Merge method 3) 合并方法
rightArray[j] = unsortedArray[middleIndex + j];
has to be change to:必须改为:
rightArray[j] = unsortedArray[middleIndex + j + 1];
4) Merge method 4) 合并方法
for (int k = leftIndex; k < rightIndex; k++)
has to be change to:必须改为:
for (int k = leftIndex; k <= rightIndex; k++)
BTW, the ref
keyword in your code is not really necessay, since you're just modifying the values inside the array and not creating a new instance of it .顺便说一句,代码中的
ref
关键字并不是必需的,因为您只是修改数组中的值而不是创建它的新实例。
private static void Merge(int[]A, int[]aux, int lo, int mid, int hi)
{
for (int k = lo; k <= hi; k++)
aux[k] = A[k];
int i = lo, j = mid + 1;
for (int k = lo; k <= hi; k++)
{
if (i > mid) A[k] = aux[j++];
else if (j > hi) A[k] = aux[i++];
else if (aux[j] < aux[i]) A[k] = aux[j++];
else A[k] = aux[i++];
}
}
private static void Sort(int[] A, int[] aux, int lo, int hi)
{
if (hi <= lo) return;
int mid = lo + (hi - lo) / 2;
Sort(A, aux, lo, mid);
Sort(A, aux, mid + 1, hi);
if (A[mid + 1] > A[mid]) return;
Merge(A, aux, lo, mid, hi);
}
public static void Sort(int[] A)
{
int[] aux = new int[A.Length];
Sort(A, aux, 0, A.Length - 1);
}
A Simple Merge Sort Implementation.一个简单的归并排序实现。
https://github.com/bharathkumarms/AlgorithmsMadeEasy/blob/master/AlgorithmsMadeEasy/MergeSort.cs https://github.com/bharathkumarms/AlgorithmsMadeEasy/blob/master/AlgorithmsMadeEasy/MergeSort.cs
using System;
using System.Collections.Generic;
using System.Linq;
namespace AlgorithmsMadeEasy
{
class MergeSort
{
public void MergeSortMethod()
{
var input = System.Console.ReadLine();
string[] sInput = input.Split(' ');
int[] numbers = Array.ConvertAll(sInput, int.Parse);
int len = numbers.Length;
MergeSort_Recursive(numbers, 0, len - 1);
for (int i = 0; i < len; i++)
{
Console.Write(numbers[i] + " ");
}
Console.ReadLine();
}
static public void MergeSort_Recursive(int[] numbers, int left, int right)
{
int mid;
if (right > left)
{
mid = (right + left) / 2;
MergeSort_Recursive(numbers, left, mid);
MergeSort_Recursive(numbers, (mid + 1), right);
DoMerge(numbers, left, (mid + 1), right);
}
}
static public void DoMerge(int[] numbers, int left, int mid, int right)
{
int[] temp = new int[numbers.Length];
int i, left_end, num_elements, tmp_pos;
left_end = (mid - 1);
tmp_pos = left;
num_elements = (right - left + 1);
while ((left <= left_end) && (mid <= right))
{
if (numbers[left] <= numbers[mid])
temp[tmp_pos++] = numbers[left++];
else
temp[tmp_pos++] = numbers[mid++];
}
while (left <= left_end)
temp[tmp_pos++] = numbers[left++];
while (mid <= right)
temp[tmp_pos++] = numbers[mid++];
for (i = 0; i < num_elements; i++)
{
numbers[right] = temp[right];
right--;
}
}
}
}
/*
Sample Input:
6 5 3 2 8
Calling Code:
MergeSort ms = new MergeSort();
ms.MergeSortMethod();
*/
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