我可以将BOOST_TEST_CASE用于非静态类成员函数吗？

Question

I am now using BOOST::UNIT_TEST framework to perform unit test, and it is a great tool to perform unit test. However, I found something inconvenient: when I add functions to test, it seems that the functions must be static or a free function as the following codes illustrate:

test_suite* ts = BOOST_TEST_SUITE( "unit_test" );

ts->add(BOOST_TEST_CASE(&static_fun));

When it is not a static function, for example,

class Abc
{
  public:
    void myfun();

};

Abc obj;
ts->add(BOOST_TEST_CASE(&(obj.myfun))); 

then, I will have C2064: term does not evaluate to a function taking 0 arguments error. Any idea that I can add the non-static class member function to the test framework? Thanks

Answer 1

I think you try to define a test fixture class? The way I use boost test in most cases looks like this:

struct MyTestFixture
{
   int test_data;
   void func() 
   {
       // some common test code
   }
};

BOOST_FIXTURE_TEST_SUITE(MyTest, MyTestFixture)

BOOST_AUTO_TEST_CASE(Test1)
{
    test_data = 3;
    func();
    // ...
}

BOOST_AUTO_TEST_CASE(Test2)
{
    // ...
}

BOOST_AUTO_TEST_SUITE_END()

Answer 2

你应该看看这里你可以使用boost::bind来实现这种情况。

ts->add(BOOST_TEST_CASE(boost::bind(&Abc::myfun, obj)));