PHP中的非静态方法如何像静态一样被调用？

Question

See the following code. I have defined a non-static method called bar in class Foo . But I am invoking the method as if it were static using the Foo::bar() syntax. It works: http://ideone.com/I45zLx .

<?php
class Foo
{
    public function bar()
    {
        echo "hello, world\n";
    }
}

Foo::bar();
?>

Why did I not get a fatal error that I am trying to invoke a non-static method as static? Could you please point me to the official PHP documentation which clarifies this point?

Answer 1

You won't get a Fatal here , instead a Strict Standard Notice.

Strict Standards: Non-static method Foo::bar() should not be called statically

Always enable error_reporting(-1); on whichever code you test. You could have seen the above on your output if you had enabled this.

See the doc here

Answer 2

I think it will generate warning. May be E_STRICT.

This main reason to define static method is you can not refer any other public member inside static function with $this object.

If you try to use $this inside your static function, you'll get a Fatal error: Using $this when not in object context.

Notion is, static method is about restriction is apply and also how is it handle during program execution.