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我如何绘制线性回归

[英]How I plot the linear regression

I am trying to plot a graph with the calculated linear regression, but I get the error "ValueError: x and y must have same first dimension". 我正在尝试使用计算的线性回归绘制图,但出现错误“ ValueError:x和y必须具有相同的第一维”。 This is a multivariate (2 variables) linear regression with 3 samples (x1,x2,x3). 这是具有3个样本(x1,x2,x3)的多元(2个变量)线性回归。

1 - First, I am calculating the linear regression correctly? 1-首先,我是否正确计算了线性回归?

2 - I know that the error comes from the plot lines. 2-我知道错误来自绘图线。 I just don't understand why I get this error. 我只是不明白为什么会出现此错误。 What is the right dimensions to put in the plot? 放置在图中的正确尺寸是多少?

    import numpy as np
    import matplotlib.pyplot as plt

    x1 = np.array([3,2])
    x2 = np.array([1,1.5])
    x3 = np.array([6,5])
    y = np.random.random(3)
    A = [x1,x2,x3]

    m,c = np.linalg.lstsq(A,y)[0]

    plt.plot(A, y, 'o', label='Original data', markersize=10)
    plt.plot(A, m*A + c, 'r', label='Fitted line')
    plt.legend()
    plt.show()


    $ python  testNumpy.py
    Traceback (most recent call last):
      File "testNumpy.py", line 22, in <module>
        plt.plot(A, m*A + c, 'r', label='Fitted line')
      File "/usr/lib/pymodules/python2.7/matplotlib/pyplot.py", line 2987, in plot
        ret = ax.plot(*args, **kwargs)
      File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 4137, in plot
        for line in self._get_lines(*args, **kwargs):
      File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 317, in     _grab_next_args
        for seg in self._plot_args(remaining, kwargs):
      File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 295, in _plot_args
        x, y = self._xy_from_xy(x, y)
      File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 237, in _xy_from_xy
        raise ValueError("x and y must have same first dimension")
    ValueError: x and y must have same first dimension

The problem here is that you're creating a list A where you want an array instead. 这里的问题是,您正在创建列表A ,而不是要使用数组。 m*A is not doing what you expect. m*A没有达到您的期望。

This: 这个:

A = np.array([x1, x2, x3])

will get rid of the error. 将摆脱错误。

NB: multiplying a list A and an integer m gives you a new list with the original content repeated m times. 注意:将列表 A整数 m相乘会得到一个新列表,原始内容重复m次。 Eg. 例如。

>>> [1, 2] * 4
[1, 2, 1, 2, 1, 2, 1, 2]

Now, m being a floating point number should have raised a TypeError (because you can only multiply lists by integers)... but m turns out to be a numpy.float64 , and it seems like when you multiply it to some unexpected thing (or a list, who knows), NumPy coerces it to an integer. 现在, m作为浮点数应该引发TypeError (因为您只能将列表乘以整数)...但是m原来是numpy.float64 ,并且看起来像将其乘以某种意外的东西(或列表(知道),NumPy将其强制为整数。

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