Python matplotlib：如何为散点图中的每个点分配不同的不透明度？

Question

I have a series of points I want to put on a scatter plot. Each point is weighted by how much I care about it. I want the dot on the scatter plot to have an opacity set according to how much I care about it.

This is my current attempt, which fails

import pandas as pd
import matplotlib.pyplot as plt

x = pd.Series([0, .2, .4, .6, .8, 1])
y = pd.Series([0, .2, .4, .6, .8, 1])
weights = pd.Series([0, .2, .4, .6, .8, 1])
# this is me trying to create RGBA tuples from the weights
colors = weights.apply(lambda x: (0,0,1,x))
plt.scatter(x, y, c=colors)
plt.show()

The plt.scatter line fails with the exception

AttributeError: 'tuple' object has no attribute 'view'

Answer 1

tcaswell is correct. I simply need to add .tolist()

colors = weights.apply(lambda x: (0,0,1,x)).tolist()