在python中打印出$和* + 2个字符之间的所有字符串

Question

i want to print out all substring in a string that has the following pattern +2 characters: for example get the substrings

$iwantthis*12
$and this*11

from the string;

$iwantthis*1231  $and this*1121

in the monent i use

 print re.search('(.*)$(.*) *',string)

and i get $iwantthis*1231 but how can i limit the number of characters after the last pattern symbol * ?

Greetings

Answer 1

In [13]: s = '$iwantthis*1231  $and this*1121'

In [14]: re.findall(r'[$].*?[*].{2}', s)
Out[14]: ['$iwantthis*12', '$and this*11']

Here,

• [$] matches $ ;
• .*?[*] matches the shortest sequence of characters followed by * ;
• .{2} matches any two characters.

Answer 2

import re
data = "$iwantthis*1231  $and this*1121"
print re.findall(r'(\$.*?\d{2})', data)

Output

['$iwantthis*12', '$and this*11']

Debuggex Demo

RegEx101 Explanation