来自频率表的 R 直方图

Question

So I've figured out how to drill my data down to a frequency table -

        Overall.Cond Freq
235            1    0
236            2    0
237            3    1
238            4    1
239            5    9
240            6    1
241            7    1
242            8    1
243            9    1

I want to plot a histogram from this, but when I do hist(dataFrameName) I get this error

Error in hist.default(veenker) : 'x' must be numeric

Why is that happening and how do I get around it?

EDIT: For those suggesting barplot as a solution (which is not the question), please consider this example of why barplot would not be a good solution.

This sample data

dt = data.frame(vals = c(1.1, 1.2, 1.3, 2.0, 3.4, 26, 35, 45),
                freq = c(  2,   3,   4,   3,   2, 15, 17, 14)) 

Using barplot(dt$freq, names.arg = dt$vals) would produce this very misleading barplot:

However, converting the data to a vector format would make much more sense using this code hist(as.vector(rep(dt$val, dt$freq))) :

Answer 1

Do you really want a histogram or a bar chart? If you insist on a histogram, you are lacking the upper boundary of your topmost bin; I will assume it is 10.

The solution provided by user2030503 is somewhat wasteful, as it re-creates the data set from the frequency table. Since you already have your frequency table computed, you can use it directly in construction of your histogram object. The latter is essentially a list in R.

Overall.Cond <- 1:10
Freq <- c(0,0,1,1,9,1,1,1,1)
myhist <-list(breaks=Overall.Cond, counts=Freq, density=Freq/diff(Overall.Cond),
              xname="Overall Cond")
class(myhist) <- "histogram"
plot(myhist)

As the bin width is 1, calculation of density could be simplified in this case; I just put it for the sake of generality.

Answer 2

Rebuild your data frame:

df= as.data.frame(cbind(Overall.Cond= 1:9, Freq= c(0,0,1,1,9,1,1,1,1)))
df

Result:

  Overall.Cond Freq
1            1    0
2            2    0
3            3    1
4            4    1
5            5    9
6            6    1
7            7    1
8            8    1
9            9    1

Then make a vector of observations and plot it:

df.freq= as.vector(rep(df$Overall.Cond, df$Freq))
hist(df.freq)

Answer 3

You can simply do

myfreq=table(df$columnofinterest)
plot(myfreq)

Answer 4

我认为它应该是一个条形图，如下所示：

barplot(dt$Freq, names.arg = dt$Overall.Cond)