Python 2.7中set vs frozenset占用的内存

Question

I was recently comparing the amount of memory occupied by a Python set to that occupied by a frozenset using Pympler :

>>> from pympler.asizeof import asizeof
>>> x = range(100)
>>> s = set(x)
>>> f0 = frozenset(x)
>>> f1 = frozenset(s)
>>> asizeof(s)
10824
>>> asizeof(f0)
10824
>>> asizeof(f1)
6728
>>> f0==f1
True

Why would a frozenset created from a set occupy a different amount of memory than one created from some other iterable? Or is this just a quirk of how Pympler approximates the amount of memory occupied by a variable in Python?

Answer 1

这是由于C中的冻结构造函数逻辑，但它确实值得CPython错误报告。