[英]How to get the item with max date value in a dictionary with mixed type values?
In the dictionary a
:在词典中
a
:
from datetime import datetime
a = {"ID":3, "CITY":"ATLANTIS", "FOUNDATION":datetime(2014,10,12), "COLLAPSE":datetime(2010,10,12), "REGENERATE":datetime(2011,10,12)}
How would you get the value which has the oldest date in this dictionary (in this case "COLLAPSE":datetime(2010,10,12)
)?您将如何获得该字典中日期最早的值(在本例中为
"COLLAPSE":datetime(2010,10,12)
)? Remember, not all values are of same data type.请记住,并非所有值都具有相同的数据类型。
If you wanted the earliest date, you want to use min()
, not max()
here;如果你想要最早的日期,你想在这里使用
min()
,而不是max()
; a datetime earlier in time sorts before another that is later.时间较早的日期时间排在较晚的日期时间之前。
You'd need to use a custom key
callable here, and return datetime.max
for any value that is not a datetime
object to discount that key:您需要在此处使用可调用的自定义
key
,并为不是datetime
对象的任何值返回datetime.max
以打折该键:
from datetime import datetime
min(a.iteritems(),
key=lambda i: i[1] if isinstance(i[1], datetime) else datetime.max)
This returns both the key and the value.这将返回键和值。
To get just the key, use:要获取密钥,请使用:
min(a, key=lambda k: a[k] if isinstance(a[k], datetime) else datetime.max)
and for just the value:仅就价值而言:
min(a.itervalues(),
key=lambda v: v if isinstance(v, datetime) else datetime.max)
In all cases only the exact syntax to get the value to compare differs.在所有情况下,只有获取要比较的值的确切语法不同。
Demo:演示:
>>> from datetime import datetime
>>> a = {"ID":3, "CITY":"ATLANTIS", "FOUNDATION":datetime(2014,10,12), "COLLAPSE":datetime(2010,10,12), "REGENERATE":datetime(2011,10,12)}
>>> min(a.iteritems(),
... key=lambda i: i[1] if isinstance(i[1], datetime) else datetime.max)
('COLLAPSE', datetime.datetime(2010, 10, 12, 0, 0))
>>> min(a, key=lambda k: a[k] if isinstance(a[k], datetime) else datetime.max)
'COLLAPSE'
>>> min(a.itervalues(),
... key=lambda v: v if isinstance(v, datetime) else datetime.max)
datetime.datetime(2010, 10, 12, 0, 0)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.