Python：如何获取导入模块中文件的绝对路径

Question

I have imported a module as:

from source.x.ReviseOnOrder import reviseOnX, x

The method reviseOnX runs another python script, say y.py which is in the same location ie /source/x . So, when executing reviseOnX , I'd like to know the full path so that I can pass the correct path to subprocess that calls y.py .

Based on other SO questions, I tried the following:

print os.path(source.x.ReviseOnOrder.__file__)

But it gives the following error:

NameError: global name 'source' is not defined

How can I find the correct path?

Answer 1

You only have references to objects imported from the module, you don't have the module object itself.

Use the inspect.getmodule() function to get the module object again:

import inspect

mod = inspect.getmodule(reviseOnX)
print os.path.abspath(mod.__file__)

Note that I am using os.path.abspath() , not os.path() . The latter would try to call the module.