如何获取在python中选择为输入文件的文件的绝对路径？

Question

I want the absolute path of the file selected as input file (from file browser in the form) using the python code below:

 for attr, document in request.files.iteritems():
        orig_filename = document.filename
        print os.path.abspath(orig_filename)
        mhash = get_hash_for_doc(orig_filename)

This prints the path of current working directory along(where the python script is executing) with the 'orig_filename' appended to it, which is the wrong path. I am using python 2.7, flask 0.12 under linux OS.

The requirement is to find the hash value of the file before uploading it to the server to check deduplication. So I need to use the algorithm by passing the file selected for hashing to another function as:

def get_hash_for_doc(orig_filename):
    mhash = None
    hash = sha1()#md5()
    with open(mfile, "rb") as f:
        for chunk in iter(lambda: f.read(128 * hash.block_size), b""):
            hash.update(chunk)
    mhash = hash.hexdigest()

    return mhash

In this function I want to read file from absolute path of the orig_filename before uploading. Avoided all other code checks here.

Answer 1

First you need to create a temp file to simulate this required file then make your process on it

import tempfile, os
try:
    fd, tmp = tempfile.mkstemp()
    with os.fdopen(fd, 'w') as out:
        out.write(file.read())
    mhash = get_hash_for_doc(tmp)
finally:
    os.unlink(tmp)

Answer 2

If you want to find a folder/file.ext, for an input file, simply use 'os.path.abspath' like:

savefile = os.path.abspath(Myinputfile)

when "Myinputfile" is a variable that contains the relative path and file name. For instance, derived from an argument define by the user.

But if you prefer to have absolute address of the folder, without file name try this:

saveloc = os.path.dirname(os.path.realpath(Myinputfile))

Answer 3

您可以使用pathlib查找所选文件的绝对路径。