[英]How to get DISINCT values of one column from a join query
I am having a query like 我正在查询
SELECT DISTINCT table_1.id_1,
table_1.id_2,
table_1_id_3
FROM table_1
INNER JOIN table_2
ON table_1.id_1 = table_2.id_1
AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
ON table_2.id_1 = table_3.id_2
AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
AND table_2.site = 'N'
AND table_3.code = 'Q'
This gives me distinct combination of id_1, id_2 and id_3 satisfying the conditions. 这给了我满足条件的id_1,id_2和id_3的独特组合。 How should the query be to get distinct values of only id_1 matching all the conditions.
查询应如何获取仅满足所有条件的id_1的不同值。
I am not posting the table contents as they are having large number of columns and as this question is a query specific one. 我不发布表内容,因为它们具有大量列,并且此问题是查询特定的。
You could remove the second and third fields from the query. 您可以从查询中删除第二和第三字段。
SELECT DISTINCT
table_1.id_1
FROM table_1
INNER JOIN table_2
ON table_1.id_1 = table_2.id_1
AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
ON table_2.id_1 = table_3.id_2
AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
AND table_2.site = 'N'
AND table_3.code = 'Q'
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