[英]How to get DISINCT values of one column from a join query
我正在查詢
SELECT DISTINCT table_1.id_1,
table_1.id_2,
table_1_id_3
FROM table_1
INNER JOIN table_2
ON table_1.id_1 = table_2.id_1
AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
ON table_2.id_1 = table_3.id_2
AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
AND table_2.site = 'N'
AND table_3.code = 'Q'
這給了我滿足條件的id_1,id_2和id_3的獨特組合。 查詢應如何獲取僅滿足所有條件的id_1的不同值。
我不發布表內容,因為它們具有大量列,並且此問題是查詢特定的。
您可以從查詢中刪除第二和第三字段。
SELECT DISTINCT
table_1.id_1
FROM table_1
INNER JOIN table_2
ON table_1.id_1 = table_2.id_1
AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
ON table_2.id_1 = table_3.id_2
AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
AND table_2.site = 'N'
AND table_3.code = 'Q'
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