[英]How to get DISINCT values of one column from a join query
我正在查询
SELECT DISTINCT table_1.id_1,
table_1.id_2,
table_1_id_3
FROM table_1
INNER JOIN table_2
ON table_1.id_1 = table_2.id_1
AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
ON table_2.id_1 = table_3.id_2
AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
AND table_2.site = 'N'
AND table_3.code = 'Q'
这给了我满足条件的id_1,id_2和id_3的独特组合。 查询应如何获取仅满足所有条件的id_1的不同值。
我不发布表内容,因为它们具有大量列,并且此问题是查询特定的。
您可以从查询中删除第二和第三字段。
SELECT DISTINCT
table_1.id_1
FROM table_1
INNER JOIN table_2
ON table_1.id_1 = table_2.id_1
AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
ON table_2.id_1 = table_3.id_2
AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
AND table_2.site = 'N'
AND table_3.code = 'Q'
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.