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如何从联接查询中获取一列的DISINCT值

[英]How to get DISINCT values of one column from a join query

我正在查询

SELECT DISTINCT table_1.id_1,
    table_1.id_2,
    table_1_id_3
FROM table_1
INNER JOIN table_2
    ON table_1.id_1 = table_2.id_1
        AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
    ON table_2.id_1 = table_3.id_2
        AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
    AND table_2.site = 'N'
    AND table_3.code = 'Q'

这给了我满足条件的id_1,id_2和id_3的独特组合。 查询应如何获取仅满足所有条件的id_1的不同值。

我不发布表内容,因为它们具有大量列,并且此问题是查询特定的。

您可以从查询中删除第二和第三字段。

SELECT DISTINCT 
    table_1.id_1    
FROM table_1
INNER JOIN table_2
    ON table_1.id_1 = table_2.id_1
        AND table_1.id_2 = table_2.id_2
INNER JOIN table_3
    ON table_2.id_1 = table_3.id_2
        AND table_2.id_2 = table_3.id_2
WHERE table_2.code = 'Y'
    AND table_2.site = 'N'
    AND table_3.code = 'Q'

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