在Python中获取包含NaN的列表的平均值

Question

I would like to know how to get the mean value of a list which contains some NaNs. By using:

np.mean(mylist)

the result as expected gives NaN which is wrong. What should i do to get the mean?

Answer 1

Use np.nanmean to ignore the NaNs:

np.nanmean(mylist)

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For example,

In [108]: np.nanmean([np.nan, 1, 2, np.nan, 3])
Out[108]: 2.0