列出包含 python 中的值的元素

Question

I am trying to print out the list which contains a specific value.

fullint = []
students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37], ['Akriti', 41], ['Harsh', 39]]
for k in students:
    fullint.append(k[1])

 fullint.sort()
 valuetobefound = fullint[1]

Here the valuetobefound variable contains the value 37.21. All I want is to print the list ['Harry', 37.21], ['Berry', 37.21] which contains the value 37.21 inside students list. I have tried

for valuetobefound in students:
    print(valuetobefound)

But this output returns all the lists ['Harry', 37.21], ['Berry', 37.21], ['Tina', 37], ['Akriti', 41], ['Harsh', 39] instead of ['Harry', 37.21], ['Berry', 37.21] . All I need is the list containing the value 37.21. Can anyone please guide me or tell me the logic to achieve this?.. Any help would be appreciated. Thank you.

Answer 1

You can try like this:

students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37], ['Akriti', 41], ['Harsh', 39]]

some_list = []
for k in students:
    if k[1] == 37.21:
        some_list.append(k)
        
print(some_list) #[['Harry', 37.21], ['Berry', 37.21]]

After that some_list should contain what you want.

Answer 2

You can use list comprehension to achieve this result, filtering out every tuple that doesn't match your needs.

>>> students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37], ['Akriti', 41], ['Harsh', 39]]
>>> my_val = 37.21
>>> students_match = [(stud, val) for (stud, val) in students if val == my_val]
>>> students_match
[('Harry', 37.21), ('Berry', 37.21)]