简体   繁体   English

Python-字典中的Pymongo列表

[英]Python - pymongo list inside dict

I'm new to python. 我是python的新手。

what I have: 我有的:

I am using mongoDb and python. 我正在使用mongoDb和python。 Using distinct dates, I want to retrieve all comments from that date. 使用不同的日期,我想检索该日期的所有评论。

example datebase: 日期库示例:

id|created_time|comment |.....
0 |2014-01-01  | hi!    |......
1 |2014-02-01  | hello! |......
2 |2014-01-01  | bye    |......`

what I tried: 我试过的

text = db.comments.find(timeout=False)
time = db.comments.distinct('created_time')

#some code
#get all distinct date and put into list
timeArray = []
for allTime in time:
    timeArray.append(allTime)

comDict = {}
for allCom in text:
    global comDict
    if(allCom['created_time'] == timeArray[1]):

        #note i'm used timeArray[1] to test the code.

        comDict.update({allCom['created_time']:allCom['comments']})

print comDict

dict cannot have duplicated keys, therefore the .update keep changing the value instead of appending it but i don't know of other way. dict不能有重复的键,因此.update不断更改值而不是附加值,但我不知道其他方法。

what I need: 我需要的:

{2014-01-01:['hi','bye'], 2014-02-01:['Hello!']}

I hope to get the above result but I am not sure how to do that. 我希望得到上述结果,但是我不确定该怎么做。 Can someone enlighten me as to what I should do, or what I did wrong? 有人能启发我应该做什么或做错了什么吗?

Thanks in advance! 提前致谢!

Don't solve it on the python level, let mongodb group the records using aggregate() : 不要在python级别上解决它,让mongodb使用aggregate()对记录进行分组:

pipe = [
    {'$match': {'$timeout': False}},
    {'$group': {'_id': '$created_time', 
                'comments': {'$push': '$comments'}}},
]
db.comments.aggregate(pipeline=pipe)

If you really want to use python: 如果您真的想使用python:

dict0={}
if not 'date' in dict0.keys(): dict0['date']=[value]
else: dict0['date'].append(value) 

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM