[英]Set subtraction while retaining order
I know with set subtraction I can do the following: 我知道通过设置减法可以执行以下操作:
l2 = set([4,3,5,2])
l1 = set([3,8])
l2 - l1
set([2, 4, 5])
How would I do this same thing, while keeping the ordering in l1
. 在保持
l1
顺序的同时,我将如何做同样的事情。 For example: 例如:
l2 = [4,3,5,2]
l1 [3,8]
# remove 3, keep other ordering
l2 - l1
[4,5,2]
l1 = [4,3,5,2]
l2 = [3]
# remove 3, keep other ordering
st = set(l2)
print([x for x in l1 if x not in st])
[4, 5, 2]
Just make l2
a set and use in
keeping elements from l1
that are not in st
. 只是让
l2
一组,并使用in
保持从要素l1
不在st
。 set lookups are 0(1)
so you still have an efficient solution. 集合查找为
0(1)
因此您仍然有一个有效的解决方案。
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