Typedef结构声明为两种类型：“typedef struct x {..} X，* XPointer”

Question

Sorry if this has been asked before, I wasn't really even sure what to search for to come up with this.

When I create a typedef struct , I usually do something like this:

typedef struct myStruct {
  int a;
  int b;
  struct myStruct *next;
} MyStruct;

So I declare it with MyStruct at the end. Then when I create functions that pass that in as a parameter, I write

int doSomething(MyStruct *ptr){

}

Yet I am collaborating with a friend on a project and I have come across his coding style, which is to also declare *MyStructP like this:

typedef struct myStruct {
  int a;
  int b;
  struct myStruct *next;
} MyStructR, *MyStructP;

And then he uses MyStructP in his functions, so his parameters look like:

int doSomething(MyStructP)

So he doesn't have to use the * in the parameter list. This confused me because when I look at the parameter list, I always look for the * to determine if the arg is a pointer or not. On top of that, I am creating a function that takes in a struct I created and a struct he created, so my arg has the * and his does not. Ultra confusing!!

Can someone give insight/comparison/advice on the differences between the two? Pros? Cons? Which way is better or worse, or more widely used? Any information at all. Thanks!

Answer 1

It is generally considered poor style to hide pointers behind typedefs, unless they are meant to be opaque handles (for example SDL_GLContext is a void* ).
This being not the case here, I agree with you that it's more confusing than helping.

Answer 2

The Linux kernel coding style says to avoid these kinds of typedefs:

Chapter 5: Typedefs

Please don't use things like "vps_t".

It's a mistake to use typedef for structures and pointers. When you see a

 vps_t a; 

in the source, what does it mean?

In contrast, if it says

 struct virtual_container *a; 

you can actually tell what "a" is.

Answer 3

Some people like to go with ideas from Hungarian Notation when they name variables. And some people take that concept further when they name types.

I think it's a matter of taste.

However, I think it obscures things (like in your example) because you'd have to dig up the declaration of the name in order to find its type. I prefer things to be obvious and explicit, and I would avoid such type names.

(And remember, typedef does not introduce a new type but merely a new name that aliases a new type.)

Answer 4

The main good reason why people occasionally typedef pointers is to represent the type as a "black box object" to the programmer and to allow its implementation to more easily be changed in the future.

For example, maybe today the type is a pointer to a struct but tomorrow the type becomes an index into some table, a handle/key of some sort, or a file descriptor. Typedef'ing this way tells the programmer that they shouldn't try things they might normally do to a pointer such as comparing it against 0 / NULL, dereferencing it (eg - directly accessing members), incrementing it, etc., as their code may become broken in the future. Of course, using a naming convention, such as your friend did, that reveals and encodes that the underlying implementation actually is a pointer conflicts with that purpose.

The other reason to do this is to make this kind of error less likely:

myStructR *ptr1, ptr2;
myStructP  ptr3, ptr4;

That's pretty weak sauce as the compiler will typically catch you misusing ptr2 later, but that is a reason given for doing this.