[英]Java: Add all possible combinations of TRUE/FALSE to a list
I have seen other posts about this, but they are not exactly like this problem. 我已经看过其他有关此问题的帖子,但它们并不完全像这个问题。
I have this code: 我有以下代码:
public static List<Boosters.Builder> GetBoosters() {
List<Boosters.Builder> boosters = new ArrayList<Boosters.Builder>();
Boosters.Builder booster = new Boosters.Builder();
booster.setLarge(Bool.TRUE).setMedium(Bool.TRUE).setSmall(Bool.TRUE);
boosters.add(booster);
booster.setLarge(Bool.FALSE).setMedium(Bool.TRUE).setSmall(Bool.FALSE);
boosters.add(booster);
booster.setLarge(Bool.TRUE).setMedium(Bool.FALSE).setSmall(Bool.TRUE);
boosters.add(booster);
booster.setLarge(Bool.TRUE).setMedium(Bool.TRUE).setSmall(Bool.FALSE);
boosters.add(booster);
// (etc, etc, etc)
return boosters;
}
Which is a part of some generated types I am doing in Java. 这是我在Java中执行的某些生成类型的一部分。 But Bool.TRUE/Bool.FALSE works sort of like normal java booleans so you can count on that. 但是Bool.TRUE / Bool.FALSE的工作方式类似于普通的Java布尔值,因此您可以依靠它。
I am trying to make a loop that will give me all possible combinations of TRUE/FALSE on: 我正在尝试创建一个循环,该循环将为我提供以下所有可能的TRUE / FALSE组合:
booster.setLarge(Bool.TRUE).setMedium(Bool.TRUE).setSmall(Bool.TRUE);
I cannot figure out how to do this nicely in a loop. 我无法弄清楚如何很好地循环执行此操作。 Can someone help me out? 有人可以帮我吗?
Use Bool#values()
to iterate over possible values of your enum: 使用Bool#values()
迭代枚举的可能值:
for (Bool large : Bool.values())
for (Bool medium : Bool.values())
for (Bool small : Bool.values())
boosters.add(new Boosters.Builder().setLarge(large).setMedium(medium).setSmall(small));
One approach would be to run an integer from 0
to 2^n
(exclusive) - where n
is the number of variables you need to assign. 一种方法是运行0
到2^n
(不包括)之间的整数-其中n
是您需要分配的变量数。
Then, you can use (x >> k) % 2
to get the value of variable number k. 然后,您可以使用(x >> k) % 2
来获取变量数k的值。
This works only for having less than 64 values (using long
variables). 这仅适用于少于64个值(使用long
变量)。
for (int x =0; x < 1<<k; x++) {
int val1 = (x >> 0) %2;
int val2 = (x >> 1) %2;
int val3 = (x >> 2) %2;
...
System.out.println("" + val1 + "," + val2 + "," + val3);
}
Note that this approach can be easily modified to any number of variables (that fits in long
) you have, by switching val1,val2,...
to an array. 请注意,通过将val1,val2,...
切换到数组val1,val2,...
可以轻松地将此方法修改为任意数量的变量(适合long
)。
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