[英]Max from a list of all shortest paths between two nodes
I have an undirected graph 我有一个无向图
I would like to calculate the max from a list of all the shortest path lengths between two nodes in the network, any ideas how I can do that? 我想从网络中两个节点之间所有最短路径长度的列表中计算出最大值,有什么想法可以做到吗?
I think you want the graph diameter which is the maximum of all-pairs shortest paths. 我认为您想要的图形直径是所有对最短路径的最大值。 https://networkx.github.io/documentation/latest/reference/generated/networkx.algorithms.distance_measures.diameter.html
https://networkx.github.io/documentation/latest/reference/generation/networkx.algorithms.distance_measures.diameter.html
If you only want to consider some subset of vertices for source and target, you might do something like: 如果只想考虑源和目标的某些顶点子集,则可以执行以下操作:
# Change these to fit your needs
sources = G.nodes() # For example, sources = [0,1,4]
targets = G.nodes()
max_shortest_path = None
for (s,t) in itertools.product(sources, targets):
if s == t: continue # Ignore
shortest_paths = list(nx.all_shortest_paths(G, s, t))
path_len = len(shortest_paths[0])
if max_shortest_path is None or path_len > len(max_shortest_path[0]):
max_shortest_path = list(shortest_paths) # Copy shortest_paths list
elif path_len == len(max_shortest_path[0]):
max_shortest_path.extend(shortest_paths)
Afterward, max_shortest_path
is a list. 之后,
max_shortest_path
是一个列表。 All elements of max_shortest_path
are lists of equal length. max_shortest_path
所有元素都是等长列表。
len(max_shortest_path[0])
will get you the length of the maximal shortest path in the graph. len(max_shortest_path[0])
将为您提供图形中最大最短路径的长度 。
The elements of max_shortest_path
are the paths of this length. max_shortest_path
的元素是此长度的路径。
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