[英]Python/Matplotlib : convert Axis <=> Data coordinates systems
My question is quite simple : in matplotlib, how can I easily convert coordinates in Axis system to/from Data system (Ideally I'm looking for a simple function output_coords = magic_func(input_coords)
) 我的问题很简单:在matplotlib中,如何轻松地将Axis系统中的坐标转换为数据系统(从理想情况来说,我正在寻找一个简单的函数
output_coords = magic_func(input_coords)
)
Actually my exact problem is : I'd like to plot an matplotlib.patches.Ellipse
with his center in Axis system but his size (width & length) in Data system. 实际上我的确切问题是:我想用他的中心在Axis系统中绘制一个
matplotlib.patches.Ellipse
,但是他的数据系统中的大小(宽度和长度)。 But the transforms.blended_transform_factory
method doesn't work in this case. 但是
transforms.blended_transform_factory
方法在这种情况下不起作用。
Thanks ! 谢谢 !
To get transformations from the Axes
instance ax
, you can use 要从
Axes
实例ax
获得转换,您可以使用
axis_to_data = ax.transAxes + ax.transData.inverted()
points_data = axis_to_data.transform(points_axis)
data_to_axis = axis_to_data.inverted()
numpy.testing.assert_allclose(points_axis, data_to_axis.transform(points_data))
No immediate solution found, need to write it by myself : 没有立即找到解决方案,需要自己编写:
def axis_data_coords_sys_transform(axis_obj_in,xin,yin,inverse=False):
""" inverse = False : Axis => Data
= True : Data => Axis
"""
xlim = axis_obj_in.get_xlim()
ylim = axis_obj_in.get_ylim()
xdelta = xlim[1] - xlim[0]
ydelta = ylim[1] - ylim[0]
if not inverse:
xout = xlim[0] + xin * xdelta
yout = ylim[0] + yin * ydelta
else:
xdelta2 = xin - xlim[0]
ydelta2 = yin - ylim[0]
xout = xdelta2 / xdelta
yout = ydelta2 / ydelta
return xout,yout
在转换教程之后 ,最简单的方法是使用ax.transLimits
。
output_coords = ax.transLimits.transform(input_coords)
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