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Question

I have a list of strings that I want to apply a method ( .split ). I know this can be done by a for loop but knowing the mentality of python I assume there is a better way, like the map function

Below is the thing I want written using for loop

config = ['a b', 'c d']

configSplit = [None] * len(config)
for x in range(len(config)):
    configSplit[x] = config[x].split()

configSplit
> [['a', 'b'], ['c', 'd']]

Answer 1

You can use a simple list comprehension , like this

>>> config = ['a b','c d']
>>> [item.split() for item in config]
[['a', 'b'], ['c', 'd']]

If you want to use map , you can pass str.split function to it. But, Python 3.x's map returns an iterable map object.

>>> map(str.split, config)
<map object at 0x7f9843a64a90>

So, you need to explicitly convert that to a list, with the list function, like this

>>> list(map(str.split, config))
[['a', 'b'], ['c', 'd']]

Answer 2

As an alternative to anwser by @thefourtheye you can use map :

config = ['a b','c d']

new_config = list(map(lambda x: x.split(), config))

print(new_config)
# [['a', 'b'], ['c', 'd']]

Answer 3

config = ['a b','c d']

Create an empty list

configSplit = list()

Iterate over each item, split, add to new list.

for item in config:
    configSplit.append(item.split())