搜索带有扩展名的文件名并打印其相对路径

Question

I have the below code to print the filename which is find criteria with file extension *.org. How could I print the relative path of the file found. Thanks in advance

def get_filelist() : 

directory = "\\\\networkpath\\123\\abc\\"
filelist = []
for root, dirs, files in os.walk(directory):
    for file in files:
        if file.endswith('Org'):
            print(str(dirs) +"\\" + str(file)) #prints empty list [] followed by filename
            filelist.append(os.path.splitext(file)[0])

return (filelist)

Please see me as novice in python

Answer 1

you need to use os.path.join :

def get_filelist() : 

    directory = "\\\\networkpath\\123\\abc\\"
    filelist = []
    for root, dirs, files in os.walk(directory):
        for file in files:
            if file.endswith('org'): # here 'org' will be in small letter
                print(os.path.join(root,file))
                filelist.append(os.path.join(root,file))

    return filelist

Answer 2

files and dirs list the children of root . dirs thus lists siblings of file . You want to print this instead:

print(os.path.relpath(os.path.join(root, file)))