[英]JSON Parsing in Objective-c[xcode 6]
I am getting the response like this. 我正在得到这样的回应。 How can I get the values?
如何获得这些值?
MODEOFTRAVEL_ID
its the key value and MODEOFTRAVELNAME
this is the other key. MODEOFTRAVEL_ID
其键值,而MODEOFTRAVELNAME
这是另一个键。
{
ColumnValuesList = (
(
1,
Flight
),
(
2,
Train
),
(
3,
"By Road"
),
(
21,
"By Bus"
)
);
TableColumns = (
"MODEOFTRAVEL_ID",
MODEOFTRAVELNAME
);
TableName = "CTZ_MODEOFTRAVEL";
},
If the question data is the contents of a variable (say d) which is an NSDictionary
then: 如果问题数据是作为
NSDictionary
的变量(例如d)的内容,则:
Example: 例:
NSDictionary *d = @{
@"ColumnValuesList" : @[
@[ @1, @"Flight" ],
@[ @2, @"Train" ],
@[ @3, @"By Road" ],
@[ @21, @"By Bus" ]
],
@"TableColumns" : @[
@"MODEOFTRAVEL_ID",
@"MODEOFTRAVELNAME"
],
@"TableName" : @"CTZ_MODEOFTRAVEL"
};
NSString *columnName0 = d[@"TableColumns"][0];
NSString *columnName1 = d[@"TableColumns"][1];
NSLog(@"columnName0: %@", columnName0);
NSLog(@"columnName1: %@", columnName1);
Output: 输出:
columnName0: MODEOFTRAVEL_ID
columnName0:MODEOFTRAVEL_ID
columnName1: MODEOFTRAVELNAMEcolumnName1:MODEOFTRAVELNAME
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