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使用Objective-C解析JSON

[英]Parsing JSON with Objective-C

For my project I have built my own api using PHP. 对于我的项目,我使用PHP构建了自己的api。 The result of json encoding basically gives me an array of entries like below json编码的结果基本上给了我如下所示的条目数组

{"terms":[
           {"term0":
               {"content":"test id",
                "userid":"100","translateto":null,
                "hastranslation":"0",
                "created":"2011-10-19 16:54:57",
                "updated":"2011-10-19 16:55:58"}
               },
           {"term1":
               {"content":"Initial content",
                "userid":"3","translateto":null,
                "hastranslation":"0",
                "created":"2011-10-19 16:51:33",
                "updated":"2011-10-19 16:51:33"
               }
           }
         ]
}

However, I've been having problems working with NSMutableDictionary and extracting "content" in Objective-C. 但是,在使用NSMutableDictionary和在Objective-C中提取“内容”时遇到了问题。

- (void) connectionDidFinishLoading:(NSURLConnection *)connection {
[connection release];

NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
[responseData release];
NSMutableDictionary *JSONval = [responseString JSONValue];
[responseString release];

if (JSONval != nil) {
    NSMutableDictionary *responseDataDict = [JSONval objectForKey:@"terms"];
    if (responseDataDict!= nil) {
        for (id key in responseDataDict) {
            NSString *content = [[responseDataDict objectForKey:key]objectForKey:@"content"];
            [terms addObject:content];
            textView.text = [textView.text stringByAppendingFormat:@"\n%@", content];
        } 
        button.enabled = YES;
    }
}

} }

Where NSLog spits out error when I send objectForKey to responseDataDict, which is a __NSArrayM according to the log. 当我将objectForKey发送到responseDataDict(根据日志为__NSArrayM)时,NSLog吐出错误的地方。

What did I do wrong here? 我在这里做错了什么?

NSMutableDictionary *responseDataDict = [JSONval objectForKey:@"terms"]; NSMutableDictionary * responseDataDict = [JSONval objectForKey:@“ terms”];

But the value of "terms" isn't a dictionary; 但是"terms"的价值不是字典。 it's an array. 这是一个数组。 Note the square brackets in your JSON string. 请注意JSON字符串中的方括号。 You should use: 您应该使用:

NSArray *terms = [JSONval objectForKey:@"terms"];

instead. 代替。

Note that each term in the array is an object (a dictionary) containing a single name (key) whose corresponding value (object) is, in turn, another object (dictionary). 请注意,数组中的每个术语都是一个对象(字典),其中包含一个名称(键),其对应的值(对象)又是另一个对象(字典)。 You should parse them as: 您应该将它们解析为:

// JSONval is a dictionary containing a single key called 'terms'
NSArray *terms = [JSONval objectForKey:@"terms"];

// Each element in the array is a dictionary with a single key
// representing a term identifier
for (NSDictionary *termId in terms) {
    // Get the single dictionary in each termId dictionary
    NSArray *values = [termId allValues];

    // Make sure there's exactly one dictionary inside termId
    if ([values count] == 1) {
        // Get the single dictionary inside termId
        NSDictionary *term = [values objectAtIndex:0];

        NSString *content = [term objectForKey:@"content"]
        …
    }
}

Add further validation as needed. 根据需要添加进一步的验证。

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