如何使用 rust-image 按程序生成图像？

Question

I'd like to learn Rust and thought it would be fun to procedurally generate images. I've no idea where to start though... piston/rust-image ? But even with that where should I begin?

Answer 1

The place to begin is the docs and the repository .

It's not immediately obvious from the landing page of the documentation, but the core type in image is ImageBuffer .

The new function allows one to construct an ImageBuffer representing an image with the given/width, storing pixels of a given type (eg RGB , or that with transparency ). One can use methods like pixels_mut , get_pixel_mut and put_pixel (the latter are below pixels_mut in the documentation) to modify the image. Eg

extern crate image;

use image::{ImageBuffer, Rgb};

const WIDTH: u32 = 10;
const HEIGHT: u32 = 10;

fn main() {
    // a default (black) image containing Rgb values
    let mut image = ImageBuffer::<Rgb<u8>>::new(WIDTH, HEIGHT);

    // set a central pixel to white
    image.get_pixel_mut(5, 5).data = [255, 255, 255];

    // write it out to a file
    image.save("output.png").unwrap();
}

which looks like:

The repo is particularly useful as a starting point, because it contains examples, in particular, it has an example of programmatically generating an image . When using a new library, I'll open the docs, and, if confused, the repo specifically to look for examples.

Answer 2

As @huon answer is 6 years old, I was getting errors reproducing the result, so I wrote this,

use image::{ImageBuffer, RgbImage};

const WIDTH:u32 = 10;
const HEIGHT:u32 = 10;

fn main() {
    let mut image: RgbImage = ImageBuffer::new(WIDTH, HEIGHT);
    *image.get_pixel_mut(5, 5) = image::Rgb([255,255,255]);
    image.save("output.png").unwrap();
}