sed awk用模式匹配替换行
[英]sed awk replace lines with a pattern match
问题描述
With awk or sed how could I replace each line after a pattern match? 
使用awk或sed，如何在模式匹配后替换每一行？ the pattern would always start as S:\\ and something else, I need the entire line from S:\\~ to the end to appear on the next lines before a blank line. 模式将始终以S：\\开头，我需要从S：\\〜到整行都显示在空白行之前的下一行中。
I have an input like this: 我有这样的输入：
S:\dir1\subfolder1longsubf
abcdefg
1234567
permissions
S:\dir2\verylongsub
some random string
some random string
S:\dir3
some random string
some random string
S:\dir4\sub2\sub3
some random string
some random string
some random string
and I need an ouput like this: 我需要这样的输出：
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir3
S:\dir3
S:\dir3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
2 个解决方案
解决方案1
3 已采纳 2015-05-04 17:52:29
I would use awk : 我会用awk ：
awk '/^S/ {line=$0} {print NF?line:""}' file
This stores the line starting with S . 这将存储以S开头的行。 Then, it prints either this stored value or an empty line if the line is empty. 然后，它打印此存储的值，或者如果该行为空，则打印一个空行。
Test 测试
$ awk '/^S/ {line=$0} {print NF?line:""}' file
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir3
S:\dir3
S:\dir3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
解决方案2
2 2015-05-04 17:56:03
使用GNU sed：
sed '/^S:/{h};/^[^S]/{g}' file
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