[英]sed awk replace lines with a pattern match
使用awk或sed,如何在模式匹配后替换每一行? 模式将始终以S:\\开头,我需要从S:\\〜到整行都显示在空白行之前的下一行中。
我有这样的输入:
S:\dir1\subfolder1longsubf
abcdefg
1234567
permissions
S:\dir2\verylongsub
some random string
some random string
S:\dir3
some random string
some random string
S:\dir4\sub2\sub3
some random string
some random string
some random string
我需要这样的输出:
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir3
S:\dir3
S:\dir3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
我会用awk
:
awk '/^S/ {line=$0} {print NF?line:""}' file
这将存储以S
开头的行。 然后,它打印此存储的值,或者如果该行为空,则打印一个空行。
$ awk '/^S/ {line=$0} {print NF?line:""}' file
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir1\subfolder1longsubf
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir2\verylongsub
S:\dir3
S:\dir3
S:\dir3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
S:\dir4\sub2\sub3
使用GNU sed:
sed '/^S:/{h};/^[^S]/{g}' file
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