如何在Windows 64位平台上的python 2.5中杀死进程？

Question

I have a python script by which i am opening three executable files as follows:

Aa=subprocess.Popen([r"..\location\learning\A.exe"])
Bb=subprocess.Popen([r"..\location\learning\new\B.bat"])
Cc=subprocess.Popen([r"..\location\learning\new\B.bat"])

All the three files are getting opened. Now,next step i want kill these three opened modules.So, firstly i tried to kill "Aa" as follows:

PROCESS_TERMINATE= 1
k = ctypes.windll.kernel32klll
handle = k.OpenProcess(PROCESS_TERMINATE, False,Aa.pid)
k.TerminateProcess(handle, -1)
k.CloseHandle(handle)

But after adding these piece of lines the three modules 'Aa','Bb' and 'Cc' they don't gets opened.So,i want to know some clean solution so that firstly all the three modules gets executed and then after a while they get closed itself. As,i am using python 2.5 on windows 64 bit platform so kindly suggest solution accordingly.

Answer 1

The process returned by subprocess.Popen() has a terminate() method to kill the child process since Python 2.6. To use that you would have to upgrade your Python install or install two versions of Python in parallel.

But a better way is usually to find out how you can tell this process to stop and use that. Many processes stop when you send them certain standard input or when you close the pipes which Popen created.