T-SQL比较一组行与其他行

Question

So I'm trying to filter one table by the values of multiple rows grouped by one column which match multiple rows of another table which are grouped by a column. For Exmaple:

###Table1###
+--------+-------+
| Symbol | Value |
+--------+-------+
| A      |     1 |
| A      |     2 |
| A      |     3 |
| B      |     9 |
| B      |     8 |
+--------+-------+

###Table2###
+--------+-------+
| Symbol | Value |
+--------+-------+
| C      |     9 |
| C      |     8 |
| D      |     1 |
| D      |     2 |
| D      |     4 |
| E      |     9 |
| E      |     8 |
| F      |     1 |
| F      |     2 |
| F      |     3 |
+--------+-------+

The query needs to return C, E, and F but not D because the values for A match the values of F, and the values of B match the values of C and E.

I hope this makes sense.

Answer 1

You can get the match by joining the tables on the value and then counting the symbols. For your data, this should work:

select t2.symbol, t1.symbol
from (select t1.*, count(*) over (partition by symbol) as cnt
      from table1 t1
     ) t1 join
     table2 t2
     on t1.value = t2.value
group by t1.symbol, t2.symbol, t1.cnt;
having count(*) = t1.cnt

This assumes:

• No duplicates in either table.
• You are looking for rows in table2 that match table1 , but table2 could have additional values not in table1 .