[英]How to convert a random telephone number from a number into words from dictionaries and how to select it from a text and convert it in python?
I am trying to convert a random telephone number from a number into words using dictionaries using the following code: 我正在尝试使用字典使用以下代码将随机电话号码从数字转换为单词:
dict_1 = {07: 'zero seven'}
dict_2 = {2: 'two', 3: 'three', 4: 'four', 5: 'five', 6: 'six', 7: 'seven', 8: 'eight'}
dict_3 = {0: 'zero', 1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five', 6: 'six', 7: 'seven', 8: 'eight', 9: 'nine'}
def main():
import re
no_tel = raw_input("Enter a phrase: ")
mat = re.search('(\d{10})', no_tel)
a_no = mat.group(0)
first_part = a_no[0:2]
second_part = a_no[2:3]
third_part = a_no[3:]
it_works = False
if dict_1.get(int(first_part)) != None:
a_print = dict_1.get(int(first_part))
it_works = True
else:
print "Error!"
if dict_2.get(int(second_part)) != None:
b_print = dict_2.get(int(second_part))
it_works = True
else:
print "Error!"
fourth_part = third_part[0]
fifth_part = third_part[1]
sixth_part = third_part[2]
seventh_part = third_part[3]
eighth_part = third_part[4]
ninth_part = third_part[5]
tenth_part = third_part[6]
if dict_3.get(int(fourth_part)) != None:
d_print = dict_3.get(int(fourth_part))
it_works = True
if dict_3.get(int(fifth_part)) != None:
e_print = dict_3.get(int(fifth_part))
it_works = True
if dict_3.get(int(sixth_part)) != None:
f_print = dict_3.get(int(sixth_part))
it_works = True
if dict_3.get(int(seventh_part)) != None:
g_print = dict_3.get(int(seventh_part))
it_works = True
if dict_3.get(int(eighth_part)) != None:
h_print = dict_3.get(int(eighth_part))
it_works = True
if dict_3.get(int(ninth_part)) != None:
i_print = dict_3.get(int(ninth_part))
it_works = True
if dict_3.get(int(tenth_part)) != None:
j_print = dict_3.get(int(tenth_part))
it_works = True
if it_works == True:
telephone = " ". join([a_print, b_print, d_print, e_print, f_print, g_print, h_print, i_print, j_print])
correct_no = re.sub ('(first_part)(second_part)(third_part)', telephone, no_tel)
print correct_no
else:
print "Error!"
if __name__ == '__main__':
main()
After running this program the output should be: 运行此程序后,输出应为:
Enter a phrase: My phone no is 0734123456
which the above code should convert to -> 上面的代码应该转换为->
My phone no is zero seven two three one two three four five six
or any other phone no in this format. 或任何其他没有此格式的电话。
Also how can the code be applied to a document containing telephone numbers? 另外,如何将代码应用于包含电话号码的文档? I do not exactly how to do it, read from text and then display the content with the telephone numbers substituted, I do not know. 我不知道该怎么做,先从文本中读取内容,然后用替换的电话号码显示内容,我不知道。
Why not just: 为什么不只是:
def phone(number):
numbers = ['zero', 'one', 'two', 'three', 'four',
'five', 'six', 'seven', 'eight', 'nine']
return ' '.join(numbers[c] for c in map(int, number))
Result: 结果:
>>> phone('0734123456')
'zero seven three four one two three four five six'
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.