从Python中的SIP URI解析电话号码

Question

Is urlparse the right module to use for this, or do we have something else?

>>> o = urlparse.urlparse('"User Name" <sips:+msisdn@domain?Accept-Contact=+sip.instance="<urn:uuid:2e7671fd-31dd-1393-dkd6-835fe09f314f>";require;explicit>', scheme='sips')
>>> print o
ParseResult(scheme='sips', netloc='', path='"User Name" <sips:+msisdn@domain', params='', query='Accept-Contact=+sip.instance="<urn:uuid:2e7671fd-31dd-1393-dkd6-835fe09f314f>";require;explicit>', fragment='')
>>> 

I expected +msisdn@domain at netloc or path , but the value in path is a bit strange.

Answer 1

你可以看看它是如何在其他库中实现的，例如在twisted中 ： https ： //github.com/twisted/twisted/blob/trunk/twisted/protocols/sip.py#L427

Answer 2

You're not parsing a SIPS URI, but an Address-Of-Record (AOR). If you extract the URI from the AOR, you'll get:

>>> o = urlparse.urlparse('sips:+msisdn@domain?Accept-Contact=+sip.instance="<urn:uuid:2e7671fd-31dd-1393-dkd6-835fe09f314f>";require;explicit')
>>> print o
ParseResult(scheme='sips', netloc='', path='+msisdn@domain', params='', query='Accept-Contact=+sip.instance="<urn:uuid:2e7671fd-31dd-1393-dkd6-835fe09f314f>";require;explicit', fragment='')

According to RFC 3986 , the userinfo@host part of the SIPS URI should go into the path component, so the result is correct here.