OpenCV Python equalizeHist 彩色图像

Question

I need to do a histogram equalization for a colored image.

First I convert the colored image to gray and give it to the equalizeHist function:

image = cv2.imread("photo.jpg")
image = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
cv2.equalizeHist(image)
cv2.imshow("equalizeHist", image)
cv2.waitKey(0)

But after this I need to convert the image back to RGB; how can i do that?

Answer 1

Source : https://www.packtpub.com/packtlib/book/Application-Development/9781785283932/2/ch02lvl1sec26/Enhancing%20the%20contrast%20in%20an%20image

import cv2
import numpy as np

img = cv2.imread('input.jpg')

img_yuv = cv2.cvtColor(img, cv2.COLOR_BGR2YUV)

# equalize the histogram of the Y channel
img_yuv[:,:,0] = cv2.equalizeHist(img_yuv[:,:,0])

# convert the YUV image back to RGB format
img_output = cv2.cvtColor(img_yuv, cv2.COLOR_YUV2BGR)

cv2.imshow('Color input image', img)
cv2.imshow('Histogram equalized', img_output)

cv2.waitKey(0)

~edit: original link is no longer available, similar idea is implemented here: Histogram Equalization of a Color image with OpenCV

Answer 2

更通用的方法是将 RGB 值转换到另一个包含发光/强度值（Luv、Lab、HSV、HSL）的空间，仅在强度平面中应用 histeq 并执行逆变换。

Answer 3

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Python Code

import cv2

def run_histogram_equalization(image_path):
    rgb_img = cv2.imread(image_path)

    # convert from RGB color-space to YCrCb
    ycrcb_img = cv2.cvtColor(rgb_img, cv2.COLOR_BGR2YCrCb)

    # equalize the histogram of the Y channel
    ycrcb_img[:, :, 0] = cv2.equalizeHist(ycrcb_img[:, :, 0])

    # convert back to RGB color-space from YCrCb
    equalized_img = cv2.cvtColor(ycrcb_img, cv2.COLOR_YCrCb2BGR)

    cv2.imshow('equalized_img', equalized_img)
    cv2.waitKey(0)

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Explanation

Histogram Equalization (HE) is a statistical approach for spreading out intensity values. In image processing, HE is used for improving the contrast of any image, that is- to make the dark portion darker and the bright portion brighter.

For a grey-scale image, each pixel is represented by the intensity value (brightness); that is why we can feed the pixel values directly to the HE function. However, that is not how it works for an RGB -formatted color image. Each channel of the R , G , and B represents the intensity of the related color, not the intensity/brightness of the image as a whole. And so, running HE on these color channels is NOT the proper way .

We should first separate the brightness of the image from the color and then run HE on the brightness. Now, there are already standardized colorspaces that encode brightness and color separately, like- YCbCr , HSV , etc.; so, we can use them here for separating and then re-merging the brightness. The proper way:

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Postscript

For HSV colorspace, HE should be run on the V channel. However, the Y channel of YCbCr is the better representer for brightness than the V channel of HSV . So, using the YCbCr format produces a more correct result for HE .

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Postscript 2

HE is too a naive technique and often produces peculiar colors and small artifacts. This is because it does not care about outliers and the location of a pixel. So, extensions like- ‎Contrast Limited Adaptive HE, Brightness preserving Bi-HE, etc. are used more commonly. Also, different noise reduction functions are executed in the post-processing phase for improving the final output.

Answer 4

You do not have to first convert your image to grayscale. You can use the approach below. A suggested solution above used the YUV colour space but I will do this example using the HSV colour space.

image = cv2.imread("photo.jpg")

# convert image from RGB to HSV
img_hsv = cv2.cvtColor(image, cv2.COLOR_RGB2HSV)

# Histogram equalisation on the V-channel
img_hsv[:, :, 2] = cv2.equalizeHist(img_hsv[:, :, 2])

# convert image back from HSV to RGB
image = cv2.cvtColor(img_hsv, cv2.COLOR_HSV2RGB)

cv2.imshow("equalizeHist", image)
cv2.waitKey(0)

Answer 5

img_yuv = cv2.cvtColor(image, cv2.COLOR_BGR2YUV)
clahe = cv2.createCLAHE(clipLimit=2.0, tileGridSize=(2,2))
img_yuv[:,:,0] = clahe.apply(img_yuv[:,:,0])
img = cv2.cvtColor(img_yuv, cv2.COLOR_YUV2BGR)
cv2.imshow("equalizeHist", img)
cv2.waitKey(0)

Answer 6

The color conversion method cv2.cvtColor() is used to convert the original image in between RGB/BGR and YUV. Here is the best coding snippet -

# convert it to grayscale
img_yuv = cv2.cvtColor(img,cv2.COLOR_BGR2YUV)

# apply histogram equalization 
img_yuv[:,:,0] = cv2.equalizeHist(img_yuv[:,:,0])
hist_eq = cv2.cvtColor(img_yuv, cv2.COLOR_YUV2BGR)

You can know more on this from here - https://www.etutorialspoint.com/index.php/311-python-opencv-histogram-equalization

Answer 7

Here is a function which would take color image as input and will return the histogram equalize image.

# function for color image equalization
def histogram_equalization(img_in):
    # segregate color streams
    b, g, r = cv2.split(img_in)
    h_b, bin_b = np.histogram(b.flatten(), 256, [0, 256])
    h_g, bin_g = np.histogram(g.flatten(), 256, [0, 256])
    h_r, bin_r = np.histogram(r.flatten(), 256, [0, 256])
    # calculate cdf
    cdf_b = np.cumsum(h_b)
    cdf_g = np.cumsum(h_g)
    cdf_r = np.cumsum(h_r)

    # mask all pixels with value=0 and replace it with mean of the pixel values
    cdf_m_b = np.ma.masked_equal(cdf_b, 0)
    cdf_m_b = (cdf_m_b - cdf_m_b.min()) * 255 / (cdf_m_b.max() - cdf_m_b.min())
    cdf_final_b = np.ma.filled(cdf_m_b, 0).astype('uint8')

    cdf_m_g = np.ma.masked_equal(cdf_g, 0)
    cdf_m_g = (cdf_m_g - cdf_m_g.min()) * 255 / (cdf_m_g.max() - cdf_m_g.min())
    cdf_final_g = np.ma.filled(cdf_m_g, 0).astype('uint8')


    cdf_m_r = np.ma.masked_equal(cdf_r, 0)
    cdf_m_r = (cdf_m_r - cdf_m_r.min()) * 255 / (cdf_m_r.max() - cdf_m_r.min())
    cdf_final_r = np.ma.filled(cdf_m_r, 0).astype('uint8')
    # merge the images in the three channels
    img_b = cdf_final_b[b]
    img_g = cdf_final_g[g]
    img_r = cdf_final_r[r]

    img_out = cv2.merge((img_b, img_g, img_r))
    # validation
    equ_b = cv2.equalizeHist(b)
    equ_g = cv2.equalizeHist(g)
    equ_r = cv2.equalizeHist(r)
    equ = cv2.merge((equ_b, equ_g, equ_r))
    # print(equ)
    # cv2.imwrite('output_name.png', equ)
    return img_out

Answer 8

i'm not sure that it works properly :

def histogram_equalize(img):
    b, g, r = cv2.split(img)
    red = cv2.equalizeHist(r)
    green = cv2.equalizeHist(g)
    blue = cv2.equalizeHist(b)
    return cv2.merge((blue, green, red))

Answer 9

If u want to equalizeHist the RGB image, u should not convert to gray instead of equalize RGB channels one by one.

So, i think maybe here is what u want:

def equalize_hist(img):
    for c in xrange(0, 2):
       img[:,:,c] = cv2.equalizeHist(img[:,:,c])

    cv2.imshow('Histogram equalized', img)
    cv2.waitKey(0)

    return img

Answer 10

you should not convert the image in to gray scale. you can do it with the colored image. but always OpenCV read the image with BGR color format. not in RGB format

import cv2

# imread needs 2 parameters. path and the flag
img = cv2.imread("photo.jpg", 1)

# convert image from BGR to HSV
img_hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)

# Histogram equalisation on the V-channel
img_hsv[:, :, 2] = cv2.equalizeHist(img_hsv[:, :, 2])

# now the img_hsv has equalized
# now convert hsv image back from HSV to RGB
imgequalized = cv2.cvtColor(img_hsv, cv2.COLOR_HSV2RGB)

cv2.imshow("original img", img)
cv2.imshow("equalizeHist", imgequalized)
cv2.waitKey(0)