[英]Converting 3D contour points to 3D binary volume
I have a set of 3D contour points that represent a closed surface, such as the following:我有一组表示闭合曲面的 3D 轮廓点,如下所示:
The contour slices are closed curves, and are always located at integer z values.轮廓切片是闭合曲线,并且始终位于整数 z 值处。 Although, there are some z values in the middle that don't have contours.虽然,中间有一些 z 值没有轮廓。
In MATLAB, I want to convert this point representation to a binary volume representation, where pixels that lie inside of the contour shape are considered as 1, and pixels outside as 0.在 MATLAB 中,我想将此点表示转换为二进制体积表示,其中位于轮廓形状内部的像素被视为 1,外部像素被视为 0。
I tried 3D triangulation and then converting the triangulated polygon to a binary volume.我尝试了 3D 三角剖分,然后将三角剖分的多边形转换为二进制体积。 Although, the triangulation doesn't respect the boundary limits that are imposed by the closed curves on each slice.虽然,三角剖分不考虑由每个切片上的闭合曲线强加的边界限制。 That is, the intra-slice points are connected indiscriminately and some round features are lost.也就是说,切片内的点被随意连接,丢失了一些圆形特征。
How can I solve this problem?我怎么解决这个问题?
我会检查Marching Cubes和Ball Pivoting以进行 3D 三角测量。
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