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具有多个条件的 Sparksql 过滤(使用 where 子句进行选择)

[英]Sparksql filtering (selecting with where clause) with multiple conditions

Hi I have the following issue:您好,我有以下问题:

numeric.registerTempTable("numeric"). 

All the values that I want to filter on are literal null strings and not N/A or Null values.我要过滤的所有值都是文字空字符串,而不是 N/A 或空值。

I tried these three options:我尝试了这三个选项:

  1. numeric_filtered = numeric.filter(numeric['LOW'] != 'null').filter(numeric['HIGH'] != 'null').filter(numeric['NORMAL'] != 'null')

  2. numeric_filtered = numeric.filter(numeric['LOW'] != 'null' AND numeric['HIGH'] != 'null' AND numeric['NORMAL'] != 'null')

  3. sqlContext.sql("SELECT * from numeric WHERE LOW != 'null' AND HIGH != 'null' AND NORMAL != 'null'")

Unfortunately, numeric_filtered is always empty.不幸的是, numeric_filtered 总是空的。 I checked and numeric has data that should be filtered based on these conditions.我检查过,数字有应该根据这些条件过滤的数据。

Here are some sample values:以下是一些示例值:

Low High Normal低 高 正常

3.5 5.0 null 3.5 5.0 空

2.0 14.0 null 2.0 14.0 空

null 38.0 null空 38.0 空

null null null空空空

1.0 null 4.0 1.0 空 4.0

Your are using logical conjunction (AND).您正在使用逻辑连词 (AND)。 It means that all columns have to be different than 'null' for row to be included.这意味着所有列都必须不同于'null'才能包含行。 Lets illustrate that using filter version as an example:让我们以使用filter版本为例来说明:

numeric = sqlContext.createDataFrame([
    ('3.5,', '5.0', 'null'), ('2.0', '14.0', 'null'),  ('null', '38.0', 'null'),
    ('null', 'null', 'null'),  ('1.0', 'null', '4.0')],
    ('low', 'high', 'normal'))

numeric_filtered_1 = numeric.where(numeric['LOW'] != 'null')
numeric_filtered_1.show()

## +----+----+------+
## | low|high|normal|
## +----+----+------+
## |3.5,| 5.0|  null|
## | 2.0|14.0|  null|
## | 1.0|null|   4.0|
## +----+----+------+

numeric_filtered_2 = numeric_filtered_1.where(
    numeric_filtered_1['NORMAL'] != 'null')
numeric_filtered_2.show()

## +---+----+------+
## |low|high|normal|
## +---+----+------+
## |1.0|null|   4.0|
## +---+----+------+

numeric_filtered_3 = numeric_filtered_2.where(
    numeric_filtered_2['HIGH'] != 'null')
numeric_filtered_3.show()

## +---+----+------+
## |low|high|normal|
## +---+----+------+
## +---+----+------+

All remaining methods you've tried follow exactly the same schema.您尝试过的所有剩余方法都遵循完全相同的模式。 What you need here is a logical disjunction (OR).您在这里需要的是逻辑分离 (OR)。

from pyspark.sql.functions import col 

numeric_filtered = df.where(
    (col('LOW')    != 'null') | 
    (col('NORMAL') != 'null') |
    (col('HIGH')   != 'null'))
numeric_filtered.show()

## +----+----+------+
## | low|high|normal|
## +----+----+------+
## |3.5,| 5.0|  null|
## | 2.0|14.0|  null|
## |null|38.0|  null|
## | 1.0|null|   4.0|
## +----+----+------+

or with raw SQL:或使用原始 SQL:

numeric.registerTempTable("numeric")
sqlContext.sql("""SELECT * FROM numeric
    WHERE low != 'null' OR normal != 'null' OR high != 'null'"""
).show()

## +----+----+------+
## | low|high|normal|
## +----+----+------+
## |3.5,| 5.0|  null|
## | 2.0|14.0|  null|
## |null|38.0|  null|
## | 1.0|null|   4.0|
## +----+----+------+

See also: Pyspark: multiple conditions in when clause另请参阅: Pyspark:when 子句中的多个条件

from pyspark.sql.functions import col, countDistinct 
totalrecordcount = df.where("ColumnName is not null").select(countDistinct("ColumnName")).collect()[0][0]

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