[英]How to concatenate strings within a br in python XPath?
Trying to solve how to concatenate strings within a <br>
is not working. 试图解决如何在一个
<br>
连接字符串是行不通的。
Here is the code: 这是代码:
<li class="attr">
<span>
Size:L
<br>
Color:RED
</span>
</li>
I tried using these but is not working: 我试过使用这些但是没有用:
color_and_size = row.xpath('.//li[@class="attr"][1]/span[1]/text()')[0]
It seems your xml structure is corrupt since no closing </br>
tag- So if you use lxml
then try soupparser that use Beautifulsoup- Or you can use standalone Beutifulsoup as below- 看来你的xml结构已损坏,因为没有关闭
</br>
标签 - 所以如果你使用lxml
然后尝试使用Beautifulsoup的soupparser-或者你可以使用如下的独立Beutifulsoup-
from bs4 import BeautifulSoup
s = """<li class="attr">
<span>
Size:L
<br>
Color:RED
</span>
</li>
"""
soup = BeautifulSoup(s)
print map(lambda x: x.text.strip().replace("\n",""),soup.find_all('span'))
Prints- Prints-
[u'Size:L Color:RED']
NB Beautifulsoup organises xml internally eg if you want valid xml of your malformed xml then try- NB Beautifulsoup在内部组织xml,例如,如果你想要有效xml的畸形xml,那么试试 -
print soup.prettify()
Prints- Prints-
<html>
<body>
<li class="attr">
<span>
Size:L
<br/>
Color:RED
</span>
</li>
</body>
</html>
If your xml
was valid the below xpath
would work- 如果您的
xml
有效,则以下xpath
将起作用 -
//li[@class='attr']/span/text()[preceding-sibling::br or following-sibling::br]
You can combine Python string methods with lxml
's XPath return values: 您可以将Python字符串方法与
lxml
的XPath返回值结合使用:
>>> import lxml.html
>>> text = '''<html>
... <li class="attr">
... <span>
... Size:L
... <br>
... Color:RED
... </span>
... </li>
... </html>'''
>>> doc = lxml.html.fromstring(text)
>>>
>>> # text nodes can contain leading and trailing whitespace characters
>>> doc.xpath('.//li[@class="attr"]/span[1]/text()')
['\n Size:L\n ', '\n Color:RED\n ']
>>>
>>> # you can use Python's strip() method
>>> [t.strip() for t in doc.xpath('.//li[@class="attr"]/span[1]/text()')]
['Size:L', 'Color:RED']
You can also test the <span>
if it contains a <br>
: ( span[br]
instead of span[1]
) 您还可以测试
<span>
如果它包含<br>
:( span[br]
而不是span[1]
)
>>> doc.xpath('.//li[@class="attr"]/span[br]/text()')
['\n Size:L\n ', '\n Color:RED\n ']
>>> [t.strip() for t in doc.xpath('.//li[@class="attr"]/span[br]/text()')]
['Size:L', 'Color:RED']
>>>
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