检查未修剪字符串列表是否包含修剪字符串

Question

We have a list of Strings which might have whitespaces at their beginning/end

We would like to check whether this list contains a string which is definitely trimmed, ie listContainingUntrimmedStrings.contains(trimmedString)

Is there a concise, preferably one-line way to do this, or we just cannot spare copying the untrimmed list into a trimmed one and perform the contains check on that / loop on the untrimmed list and do trimmed equality check on the elements one-by-one / other verbose solution?

Answer 1

You can do that in a functional style using stream operations:

listContainingUntrimmedStrings.stream()
    .map(String::trim)                     // lazily apply trimming to each element in the list
    .anyMatch(trimmedString::equals)       // check if any of those elements equals your initial string (assuming that `trimmedString` is NOT NULL)