如何在django过滤器中做小于或等于和大于等于？

Question

How to do less than or equal to and greater than equal to in django filter? Like , I want to get value around :- 10<=val<=50 in django view.
For this I used some query in sql like this :-

select count(*) from table_name where gender='MALE' and age<=50 and age>=10;

I tried something like this in django view :-

tablename.objects.filter(Q(gender='MALE'),Q(age__lte=50) & Q(age__gte=10)).count()

But I got different values. In sql I got 65 and in django I got 29. sql answer is correct. Please help me to do comparison in django view.

Answer 1

Why don't you use the _range function?

filter(gender='MALE', age__range=(10, 50))

See here: https://docs.djangoproject.com/en/1.7/ref/models/querysets/#range

Edit for new link: https://docs.djangoproject.com/en/3.0/ref/models/querysets/#range

Answer 2

如果你真的想使用>=和<=你可以写：

Modelname.objects.filter(gender='MALE', age__gte = 10, age__lte = 50).count()