[英]Python 'str' object has no attribute 'name' when using a function variable to call a class instance
I'm just starting to learn programming with python. 我刚刚开始学习使用python编程。 I'm trying to make a game similar to Pokemon, and I'm trying to apply OOP into agame.
我正在尝试制作类似于《口袋妖怪》的游戏,并且试图在游戏中应用OOP。
I started by making a Pokemon class, and adding class-defined attributes such as name, HP, etype, attacks. 首先,制作一个Pokemon类,并添加类定义的属性,例如名称,HP,etype,攻击。 "attacks" is a dictionary of lists.
“攻击”是列表的字典。
My problem now is I'm trying to develop a simple battle engine where I can switch out pokemons. 我现在的问题是,我正在尝试开发一个简单的战斗引擎,在这里我可以换掉口袋妖怪。 For this reason, I made a function/method name fight().
因此,我将函数/方法命名为fight()。
Inside that I have a variable named current_pokemon.name so whenever I switch out the pokemon, I can use the new pokemon's name, attacks, etc. 在其中,我有一个名为current_pokemon.name的变量,因此每当切换出神奇宝贝时,我都可以使用新的神奇宝贝的名称,攻击等。
I used raw_input to return a string that replaces current_pokemon, which has a .name attribute to call on a pikachu instance. 我使用了raw_input返回一个替换current_pokemon的字符串,该字符串具有一个在皮卡丘实例上调用的.name属性。 Instead, I get the 'str' object has no attribute.
相反,我得到的'str'对象没有属性。 Why doesn't this work?
为什么不起作用? It worked outside the function fight() when I explicitly wrote pikachu.attribute.
当我显式编写pikachu.attribute时,它在功能fight()之外起作用。
class Pokemon(object):
def __init__(self, name, HP, etype, attacks):
self.name = name
self.HP = HP
self.etype = etype
self.attacks = attacks #2 attacks with name, dmg, type and power points
geodude = Pokemon("Geodude", 100, "Ground",
attacks =
{"Tackle":["Tackle",30,"Normal","35"],
"Rollout":["Rollout",50,"Rock","20"]
})
#attacks = {attack:[attack_name, dmg, type, PP]}
pikachu = Pokemon("Pikachu", 100, "Lightning",
attacks =
{"Thunder Shock":["Thunder Shock",40,"Electric"],
"Quick Attack":["Quick Attack",40,"Normal"]
})
#selects pikachu's attack
print "Pokemon's name is", (pikachu.name)
print "Pikachu's %s attack damages %d" % ((pikachu.attacks["Thunder Shock"][0]),(pikachu.attacks["Thunder Shock"][1]))
pikachu.HP = pikachu.HP - geodude.attacks["Rollout"][1]
print "Pikachu's HP is", (pikachu.HP)
pikachu.HP = pikachu.HP - geodude.attacks["Tackle"][1]
print "Pikachu's HP is", (pikachu.HP)
#Pokemon Battle test with stored variable
#Value selector - replace all var attributes using an easy function
#Use Solution 2
def fight():
current_pokemon = raw_input("pikachu or geodude? > ")
print current_pokemon.name
print current_pokemon.attacks
fight()
Output: 输出:
Pokemon's name is Pikachu
Pikachu's Thunder Shock attack damages 40
Pikachu's HP is 50
Pikachu's HP is 20
pikachu or geodude? > pikachu
Traceback (most recent call last):
File "poke_game_stack.py", line 40, in <module>
fight()
File "poke_game_stack.py", line 36, in fight
print current_pokemon.name
AttributeError: 'str' object has no attribute 'name'
Please help noob me with this simple problem! 请帮助菜鸟这个简单的问题! Thanks!
谢谢!
raw_input()
always returns a string; raw_input()
总是返回一个字符串; it will not return an object you stored by the same name. 它不会返回您使用相同名称存储的对象。
Store your pokemons in a dictionary, (mapping string to object) then use the string from raw_input()
to map to one of those objects: 将您的神奇宝贝存储在字典中(将字符串映射到对象),然后使用
raw_input()
的字符串映射到这些对象之一:
pokemons = {
'geodude': Pokemon("Geodude", 100, "Ground",
attacks =
{"Tackle":["Tackle",30,"Normal","35"],
"Rollout":["Rollout",50,"Rock","20"]
}),
'pikachu': Pokemon("Pikachu", 100, "Lightning",
attacks =
{"Thunder Shock":["Thunder Shock",40,"Electric"],
"Quick Attack":["Quick Attack",40,"Normal"]
}),
}
def fight():
current_pokemon_name = raw_input("pikachu or geodude? > ")
current_pokemon = pokemons[current_pokemon_name]
print current_pokemon.name
print current_pokemon.attacks
current_pokemon = raw_input("pikachu or geodude? > ")
print current_pokemon.name
print current_pokemon.attacks
The raw_input()
method returns a str
, and strings have no property such as name
or attacks
. raw_input()
方法返回一个str
,并且字符串没有诸如name
或attacks
属性。
The function reads a line from input, converts it to a string (stripping a trailing newline), and returns that.
该函数从输入中读取一行, 将其转换为字符串 (带末尾的换行符),然后将其返回。 When EOF is read, EOFError is raised.
读取EOF时,将引发EOFError。
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