Python-如何将整个numpy数组一次放入Queue.Queue中，但分别检索每一行

Question

Let's say I have a 2-d numpy array with 10 rows

for example

array([[  23425.     ,  521331.40625],
   [  23465.     ,  521246.03125],
   [  23505.     ,  528602.8125 ],
   [  23545.     ,  531934.75   ],
   [  23585.     ,  534916.375  ],
   [  23625.     ,  544971.9375 ],
   [  23665.     ,  544707.5625 ],
   [  23705.     ,  532729.25   ],
   [  23745.     ,  540303.0625 ],
   [  23865.     ,  527971.1875 ]])

Is there a way to place that whole array in a queue (from python's collections) all at once, without iterating over the array and using put() for each row, and then be able to retrieve each row separately using the queue.get() function?

For example a first call to the queue.get() would retrieve [23865., 527971.1875 ] and a second call would retrieve [23745., 540303.0625 ]

Answer 1

You can use the map keyword to avoid iterating over the array:

map(queue.put, myArray)

or in python 3.x:

list(map(queue.put, myArray))