在python 2.x中两个不同模块中的两个函数之间共享数据

Question

I know this is possible using thread local in python but for some reason I am unable to find the exact syntax to achieve this. I have following sample code to test this but this is not working -

module1.py

import threading

def print_value():
    local = threading.local() // what should I put here? this is actually creating a new thread local instead of returning a thread local created in main() method of module2.
    print local.name;

module2.py

import module1

if __name__ == '__main__':
    local = threading.local()
    local.name = 'Shailendra'
    module1.print_value()

Edit1 - Shared data should be available to only a thread which will invoke these functions and not to all the threads in the system. One example is request id in a web application.

Answer 1

In module 1, define a global variable that is a threading.local

module1

import threading

shared = threading.local()

def print_value():
    print shared.name

module2

import module1

if __name__ == '__main__':
    module1.shared.name = 'Shailendra'
    module1.print_value()

Answer 2

If it's within the same process, why not use a singleton ?

import functools

def singleton(cls):
    ''' Use class as singleton. '''

    cls.__new_original__ = cls.__new__

    @functools.wraps(cls.__new__)
    def singleton_new(cls, *args, **kw):
       it =  cls.__dict__.get('__it__')
       if it is not None:
           return it

       cls.__it__ = it = cls.__new_original__(cls, *args, **kw)
       it.__init_original__(*args, **kw)
       return it

   cls.__new__ = singleton_new
   cls.__init_original__ = cls.__init__
   cls.__init__ = object.__init__

   return cls

@singleton
class Bucket(object):
    pass

Now just import Bucket and bind some data to it

from mymodule import Bucket
b = Bucket()
b.name = 'bob'
b.loves_cats = True